What is the solution for (dN)/(dt)=k(1-N)^2 ?

The solution for (dN)/(dt)=k(1-N)^2 is N=-1/(kt+c_{1)}+(kt)/(kt+c_{1)}+(c_{1})/(kt+c_{1)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

(dN)/(dt)=k(1-N)^2

\frac{d N}{d t} = k (1 - N)^{2}

N = - \frac{1}{k t + c _{1}} + \frac{k t}{k t + c _{1}} + \frac{c _{1}}{k t + c _{1}}

Solution steps

\frac{d N}{d t} = k (1 - N)^{2}

Solve separable ODE:

N = - \frac{1}{k t + c _{1}} + \frac{k t}{k t + c _{1}} + \frac{c _{1}}{k t + c _{1}}

N = - \frac{1}{k t + c _{1}} + \frac{k t}{k t + c _{1}} + \frac{c _{1}}{k t + c _{1}}

What is the solution for (dN)/(dt)=k(1-N)^2 ?
The solution for (dN)/(dt)=k(1-N)^2 is N=-1/(kt+c_{1)}+(kt)/(kt+c_{1)}+(c_{1})/(kt+c_{1)}