What is the ((1/y)-(x/y))dx+(x^2*cos(y))dy=0,y(1)=pi ?

The ((1/y)-(x/y))dx+(x^2*cos(y))dy=0,y(1)=pi is 0

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((1/y)-(x/y))dx+(x^2*cos(y))dy=0,y(1)=pi

((\frac{1}{y}) - (\frac{x}{y})) d x + (x^{2} \cdot cos (y)) d y = 0, y (1) = π

0

Solution steps

For

((\frac{1}{y}) - (\frac{x}{y})) d x + (x^{2} \cdot cos (y)) d y \circ y (1)

substitute

((\frac{1}{y}) - (\frac{x}{y})) d x + (x^{2} \cdot cos (y)) d y

with

0, y (1)

with

π

= 0 \circ π

0 \circ π = 0

= 0

What is the ((1/y)-(x/y))dx+(x^2*cos(y))dy=0,y(1)=pi ?
The ((1/y)-(x/y))dx+(x^2*cos(y))dy=0,y(1)=pi is 0