What is the solution for y^'+3.2x^4*y=6.4x^4 ?

The solution for y^'+3.2x^4*y=6.4x^4 is y=(e^{-0.64x^5+c_{1}})/(3.2)+(6.4)/(3.2)

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y^'+3.2x^4*y=6.4x^4

y^{^{'}} + 3.2 x^{4} \cdot y = 6.4 x^{4}

y = \frac{e ^{- 0.64 x^{5} + c_{1}}}{3.2} + \frac{6.4}{3.2}

Solution steps

y^{'} (x) + 3.2 x^{4} \cdot y = 6.4 x^{4}

Solve separable ODE:

y = \frac{e ^{- 0.64 x^{5} + c_{1}}}{3.2} + \frac{6.4}{3.2}

y = \frac{e ^{- 0.64 x^{5} + c_{1}}}{3.2} + \frac{6.4}{3.2}

What is the solution for y^'+3.2x^4*y=6.4x^4 ?
The solution for y^'+3.2x^4*y=6.4x^4 is y=(e^{-0.64x^5+c_{1}})/(3.2)+(6.4)/(3.2)