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Popular Calculus >

y^'=x^2y+x^2

Solution

y^{^{'}} = x^{2} y + x^{2}

Solution

y = e^{\frac{x ^{3}}{3} + c_{1}} - 1

Solution steps

y^{'} (x) = x^{2} y + x^{2}

Solve separable ODE:

y = e^{\frac{x ^{3}}{3} + c_{1}} - 1

y = e^{\frac{x ^{3}}{3} + c_{1}} - 1

Graph

Popular Examples

y^'=y-y^3,y(0)=2

(dy)/(dx)=x-2xy

((1/y)-(x/y))dx+(x^2*cos(y))dy=0,y(1)=pi

y^'-2y=0,y(x,1)=x^2

Frequently Asked Questions (FAQ)

What is the solution for y^'=x^2y+x^2 ?
The solution for y^'=x^2y+x^2 is y=e^{(x^3)/3+c_{1}}-1