What is the solution for (x^2+1)((dy)/(dx))+3x(y-1)=0,y(0)=5 ?

The solution for (x^2+1)((dy)/(dx))+3x(y-1)=0,y(0)=5 is y= 4/((x^2+1)^{3/2)}+1

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(x^2+1)((dy)/(dx))+3x(y-1)=0,y(0)=5

(x^{2} + 1) (\frac{d y}{d x}) + 3 x (y - 1) = 0, y (0) = 5

y = \frac{4}{( x ^{2} + 1 ) ^{\frac{3}{2}}} + 1

Solution steps

(x^{2} + 1) (\frac{d y}{d x}) + 3 x (y - 1) = 0

Solve separable ODE:

y = \frac{4}{( x ^{2} + 1 ) ^{\frac{3}{2}}} + 1

y = \frac{4}{( x ^{2} + 1 ) ^{\frac{3}{2}}} + 1

What is the solution for (x^2+1)((dy)/(dx))+3x(y-1)=0,y(0)=5 ?
The solution for (x^2+1)((dy)/(dx))+3x(y-1)=0,y(0)=5 is y= 4/((x^2+1)^{3/2)}+1