What is the solution for 2xyy^'=x+3 ?

The solution for 2xyy^'=x+3 is y=sqrt(x+3ln(x)+c_{1)},y=-sqrt(x+3ln(x)+c_{1)}

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2xyy^'=x+3

2 x y y^{^{'}} = x + 3

y = x + 3 ln (x) + c_{1}, y = - x + 3 ln (x) + c_{1}

Solution steps

2 x y y^{'} (x) = x + 3

Solve separable ODE:

y = x + 3 ln (x) + c_{1}, y = - x + 3 ln (x) + c_{1}

y = x + 3 ln (x) + c_{1}, y = - x + 3 ln (x) + c_{1}

What is the solution for 2xyy^'=x+3 ?
The solution for 2xyy^'=x+3 is y=sqrt(x+3ln(x)+c_{1)},y=-sqrt(x+3ln(x)+c_{1)}