What is the solution for 2x^2+3x^2-2xy(dy)/(dx)=0 ?

The solution for 2x^2+3x^2-2xy(dy)/(dx)=0 is y=sqrt((5x^2)/2+c_{1)},y=-sqrt((5x^2)/2+c_{1)}

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2x^2+3x^2-2xy(dy)/(dx)=0

2 x^{2} + 3 x^{2} - 2 x y \frac{d y}{d x} = 0

y = \frac{5 x ^{2}}{2} + c_{1}, y = - \frac{5 x ^{2}}{2} + c_{1}

Solution steps

2 x^{2} + 3 x^{2} - 2 x y \frac{d y}{d x} = 0

Solve separable ODE:

y = \frac{5 x ^{2}}{2} + c_{1}, y = - \frac{5 x ^{2}}{2} + c_{1}

y = \frac{5 x ^{2}}{2} + c_{1}, y = - \frac{5 x ^{2}}{2} + c_{1}

What is the solution for 2x^2+3x^2-2xy(dy)/(dx)=0 ?
The solution for 2x^2+3x^2-2xy(dy)/(dx)=0 is y=sqrt((5x^2)/2+c_{1)},y=-sqrt((5x^2)/2+c_{1)}