Solution
Solution
Solution steps
Solve separable ODE:
Graph
Popular Examples
y^'+4y=0,y(0)=5y^'-x^2y=ye^{-x}(dy)/(dx)= 1/8 (y^{1/2})(cos(y^{1/2}))^2(x^2dy-y^2dx)/((x-y)^2)=0y^'=(y^2+xy^2)/(x^2y-x^2)
Frequently Asked Questions (FAQ)
What is the solution for x^3dy+x^2ydx+ydx=xdy ?
The solution for x^3dy+x^2ydx+ydx=xdy is y=(c_{1}x)/(x^2-1)