What is the solution for y^'=2sqrt(y+1)cos(x) ?

The solution for y^'=2sqrt(y+1)cos(x) is y=sin^2(x)+c_{1}sin(x)+(c_{1}^2)/4-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

y^'=2sqrt(y+1)cos(x)

y^{^{'}} = 2 y + 1 cos (x)

y = sin^{2} (x) + c_{1} sin (x) + \frac{c _{1}^{2}}{4} - 1

Solution steps

y^{'} (x) = 2 y + 1 cos (x)

Solve separable ODE:

y = sin^{2} (x) + c_{1} sin (x) + \frac{c _{1}^{2}}{4} - 1

y = sin^{2} (x) + c_{1} sin (x) + \frac{c _{1}^{2}}{4} - 1

What is the solution for y^'=2sqrt(y+1)cos(x) ?
The solution for y^'=2sqrt(y+1)cos(x) is y=sin^2(x)+c_{1}sin(x)+(c_{1}^2)/4-1