What is the solution for (dy}{dx}=\frac{20x^4)/y ,y>0,x>0 ?

The solution for (dy}{dx}=\frac{20x^4)/y ,y>0,x>0 is y=sqrt(8x^5+c_{1)},y=-sqrt(8x^5+c_{1)}

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(dy}{dx}=\frac{20x^4)/y ,y>0,x>0

\frac{d y}{d x} = \frac{20 x ^{4}}{y}, y > 0, x > 0

y = 8 x^{5} + c_{1}, y = - 8 x^{5} + c_{1}

Solution steps

\frac{d y}{d x} = \frac{20 x ^{4}}{y}

Solve separable ODE:

y = 8 x^{5} + c_{1}, y = - 8 x^{5} + c_{1}

y = 8 x^{5} + c_{1}, y = - 8 x^{5} + c_{1}

What is the solution for (dy}{dx}=\frac{20x^4)/y ,y>0,x>0 ?
The solution for (dy}{dx}=\frac{20x^4)/y ,y>0,x>0 is y=sqrt(8x^5+c_{1)},y=-sqrt(8x^5+c_{1)}