What is the slope of 4y^3+7x^8=5y+6x,(1,1) ?

The slope of 4y^3+7x^8=5y+6x,(1,1) is -50/7

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slope of 4y^3+7x^8=5y+6x,(1,1)

slope

4 y^{3} + 7 x^{8} = 5 y + 6 x, (1, 1)

- \frac{50}{7}

Solution steps

4 y^{3} + 7 x^{8} = 5 y + 6 x

Use implicit differentiation to find the slope of

4 y^{3} + 7 x^{8} = 5 y + 6 x

Implicit Derivative

\frac{d y}{d x}

4 y^{3} + 7 x^{8} = 5 y + 6 x : \frac{6 - 56 x ^{7}}{12 y ^{2} - 5}

\frac{6 - 56 x ^{7}}{12 y ^{2} - 5}

Find the slope at

(1, 1) : - \frac{50}{7}

- \frac{50}{7}

n = 1 \sum \infty (\frac{5}{2})^{n}

\frac{d}{d x} (\frac{( x ^{3} + 8 )}{2 x})^{7}

u^{6}

x \to 0 lim ((\frac{1}{x})^{x})

\int \frac{1}{( 3 x + 2 ) ^{2}} d x

What is the slope of 4y^3+7x^8=5y+6x,(1,1) ?
The slope of 4y^3+7x^8=5y+6x,(1,1) is -50/7