What is the derivative of y=x^3+1 ?

The derivative of y=x^3+1 is 3x^2

What is the first derivative of y=x^3+1 ?

The first derivative of y=x^3+1 is 3x^2

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derivative of

y = x^{3} + 1

3 x^{2}

Solution steps

\frac{d}{d x} (x^{3} + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) + \frac{d}{d x} (1)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (1) = 0

= 3 x^{2} + 0

Simplify

= 3 x^{2}

\frac{6 x + 8 x ^{2}}{( 3 + 8 x ) ^{2}}

\frac{d x}{d t} = - 2 x + t

x, at 4

x \to 0 lim ((1 - 5 x)^{\frac{3}{x}})

x^{3} csc (x)

What is the derivative of y=x^3+1 ?
The derivative of y=x^3+1 is 3x^2
What is the first derivative of y=x^3+1 ?
The first derivative of y=x^3+1 is 3x^2