What is the solution for (dx)/(dt)=-2x+t ?

The solution for (dx)/(dt)=-2x+t is x=(2t-1)/4+(c_{1})/(e^{2t)}

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(dx)/(dt)=-2x+t

\frac{d x}{d t} = - 2 x + t

x = \frac{2 t - 1}{4} + \frac{c _{1}}{e ^{2 t}}

Solution steps

\frac{d x}{d t} = - 2 x + t

Solve linear ODE:

x = \frac{2 t - 1}{4} + \frac{c _{1}}{e ^{2 t}}

x = \frac{2 t - 1}{4} + \frac{c _{1}}{e ^{2 t}}

x, at 4

x \to 0 lim ((1 - 5 x)^{\frac{3}{x}})

x^{3} csc (x)

\frac{d}{d x} (ln ((ln (x))^{2}))

\int \frac{1 - sin ^{3} ( x )}{sin ^{2} ( x )} d x

What is the solution for (dx)/(dt)=-2x+t ?
The solution for (dx)/(dt)=-2x+t is x=(2t-1)/4+(c_{1})/(e^{2t)}