Solution

Solution

Solution steps
Apply the constant multiplication rule:
Apply Series Comparison Test:converges

Popular Examples

sum from n=1 to infinity of (2n)/(3n+6)sum from n=0 to infinity of n/(6^n)sum from n=2 to infinity of 4/(n(n-1))sum from n=1 to infinity of 1/(6^{n+1)}sum from n=1 to infinity of ((-2)^n)/n

Frequently Asked Questions (FAQ)

  • What is the sum from n=1 to infinity of 2/(n^3+4) ?

    The sum from n=1 to infinity of 2/(n^3+4) is converges