Solution

Solution

Solution steps
Apply Series Ratio Test:converges

Popular Examples

sum from n=1 to infinity of ((-2)^n)/nsum from n=1 to infinity of (n!)/(6^n)sum from n=1 to infinity of (2^n)/(n^n)sum from n=0 to infinity of nln(n)sum from n=0 to infinity of 2/(10^n)

Frequently Asked Questions (FAQ)

  • What is the sum from n=1 to infinity of 1/(6^{n+1)} ?

    The sum from n=1 to infinity of 1/(6^{n+1)} is converges