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Popular Calculus >

integral from-1 to x of x+1

Solution

\int_{- 1}^{x} x + 1 d x

Solution

\frac{x ^{2} - 1}{2} + x + 1

Solution steps

\int_{- 1}^{x} x + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{x} x d x + \int_{- 1}^{x} 1 d x

\int_{- 1}^{x} x d x = \frac{x ^{2} - 1}{2}

\int_{- 1}^{x} 1 d x = x + 1

= \frac{x ^{2} - 1}{2} + x + 1

Popular Examples

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Frequently Asked Questions (FAQ)

What is the integral from-1 to x of x+1 ?
The integral from-1 to x of x+1 is (x^2-1)/2+x+1