What is the integral from 500 to 10x+500 of 1/75000 ?

The integral from 500 to 10x+500 of 1/75000 is (x+50)/(7500)-1/150

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integral from 500 to 10x+500 of 1/75000

\int_{500}^{10 x + 500} \frac{1}{75000} d y

\frac{x + 50}{7500} - \frac{1}{150}

Solution steps

\int_{500}^{10 x + 500} \frac{1}{75000} d y

Integral of a constant:

\int a d x = a x

= [\frac{1}{75000} y]_{500}^{10 x + 500}

Compute the boundaries:

\frac{x + 50}{7500} - \frac{1}{150}

= \frac{x + 50}{7500} - \frac{1}{150}

What is the integral from 500 to 10x+500 of 1/75000 ?
The integral from 500 to 10x+500 of 1/75000 is (x+50)/(7500)-1/150