What is the integral from 1 to 6 of 9^x ?

The integral from 1 to 6 of 9^x is (265716)/(ln(3))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral from 1 to 6 of 9^x

\int_{1}^{6} 9^{x} d x

\frac{265716}{ln ( 3 )}

Decimal

241865.12634 \dots

Solution steps

\int_{1}^{6} 9^{x} d x

\int a^{x} d x = \frac{a ^{x}}{ln a}

= [\frac{9 ^{x}}{ln ( 9 )}]_{1}^{6}

Simplify

ln (9) : 2 ln (3)

= [\frac{9 ^{x}}{2 ln ( 3 )}]_{1}^{6}

Compute the boundaries:

\frac{265716}{ln ( 3 )}

= \frac{265716}{ln ( 3 )}

What is the integral from 1 to 6 of 9^x ?
The integral from 1 to 6 of 9^x is (265716)/(ln(3))