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Popular Calculus >

integral from 0 to 2 of (6x^2-5)

Solution

\int_{0}^{2} (6 x^{2} - 5) d x

Solution

6

Solution steps

\int_{0}^{2} 6 x^{2} - 5 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{2} 6 x^{2} d x - \int_{0}^{2} 5 d x

\int_{0}^{2} 6 x^{2} d x = 16

\int_{0}^{2} 5 d x = 10

= 16 - 10

Simplify

= 6

Graph

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Frequently Asked Questions (FAQ)

What is the integral from 0 to 2 of (6x^2-5) ?
The integral from 0 to 2 of (6x^2-5) is 6