What is the integral from 2 to infinity of ax^{-5} ?

The integral from 2 to infinity of ax^{-5} is a/(64)

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integral from 2 to infinity of ax^{-5}

\int_{2}^{\infty} a x^{- 5} d x

\frac{a}{64}

Solution steps

\int_{2}^{\infty} a x^{- 5} d x

Compute the indefinite integral:

\int a x^{- 5} d x = - \frac{a}{4 x ^{4}} + C

Compute the boundaries:

\int_{2}^{\infty} a x^{- 5} d x = 0 - (- \frac{a}{64})

= 0 - (- \frac{a}{64})

Simplify

= \frac{a}{64}

What is the integral from 2 to infinity of ax^{-5} ?
The integral from 2 to infinity of ax^{-5} is a/(64)