What is the integral from-8 to 0 of 1/(\sqrt[3]{x)} ?

The integral from-8 to 0 of 1/(\sqrt[3]{x)} is -6(-1)^{2/3}

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integral from-8 to 0 of 1/(\sqrt[3]{x)}

- 6 (- 1)^{\frac{2}{3}}

Solution steps

Apply the Power Rule

= [\frac{3}{2} x^{\frac{2}{3}}]_{- 8}^{0}

Compute the boundaries:

- 6 (- 1)^{\frac{2}{3}}

= - 6 (- 1)^{\frac{2}{3}}

What is the integral from-8 to 0 of 1/(\sqrt[3]{x)} ?
The integral from-8 to 0 of 1/(\sqrt[3]{x)} is -6(-1)^{2/3}