What is the integral of xe^{20x} ?

The integral of xe^{20x} is 1/400 (e^{20x}*20x-e^{20x})+C

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integral of xe^{20x}

\int x e^{20 x} d x

\frac{1}{400} (e^{20 x} \cdot 20 x - e^{20 x}) + C

Solution steps

\int x e^{20 x} d x

Apply u-substitution

= \int \frac{e ^{u} u}{400} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{400} \cdot \int e^{u} u d u

Apply Integration By Parts

= \frac{1}{400} (e^{u} u - \int e^{u} d u)

\int e^{u} d u = e^{u}

= \frac{1}{400} (e^{u} u - e^{u})

Substitute back

u = 20 x

= \frac{1}{400} (e^{20 x} \cdot 20 x - e^{20 x})

Add a constant to the solution

= \frac{1}{400} (e^{20 x} \cdot 20 x - e^{20 x}) + C

What is the integral of xe^{20x} ?
The integral of xe^{20x} is 1/400 (e^{20x}*20x-e^{20x})+C