derivative y=2cot(t)-e^{-t}

Lösung

ableitung von

y = 2 cot (t) - e^{- t}

- 2 csc^{2} (t) + e^{- t}

Schritte zur Lösung

\frac{d}{d t} (2 cot (t) - e^{- t})

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (2 cot (t)) - \frac{d}{d t} (e^{- t})

\frac{d}{d t} (2 cot (t)) = - 2 csc^{2} (t)

\frac{d}{d t} (e^{- t}) = - e^{- t}

= - 2 csc^{2} (t) - (- e^{- t})

Vereinfache

= - 2 csc^{2} (t) + e^{- t}

\int \frac{( 1 + x ) ^{3}}{x} d x

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\frac{\partial}{\partial x} (x^{\frac{1}{3}} \cdot y^{\frac{2}{3}})

d er i v a t i v e y = (ln (x))^{4}

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