What is the integral from 0 to pi of 6sin(x) ?

The integral from 0 to pi of 6sin(x) is 12

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integral from 0 to pi of 6sin(x)

\int_{0}^{π} 6 sin (x) d x

12

Solution steps

\int_{0}^{π} 6 sin (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 6 \cdot \int_{0}^{π} sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= 6 [- cos (x)]_{0}^{π}

Compute the boundaries:

2

= 6 \cdot 2

Simplify

= 12

\int sec (t) (9 sec (t) + 7 tan (t)) d t

\frac{10}{s ^{2} + 2 s + 5}

\int \frac{1}{x ^{2} - 441} d x

\int - 16 sin (4 x - \frac{π}{2}) d x

n = 1 \sum \infty \frac{1}{n} - \frac{1}{n + 2}

What is the integral from 0 to pi of 6sin(x) ?
The integral from 0 to pi of 6sin(x) is 12