What is the sum from n=1 to infinity of 1/n-1/(n+2) ?

The sum from n=1 to infinity of 1/n-1/(n+2) is 3/2

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sum from n=1 to infinity of 1/n-1/(n+2)

n = 1 \sum \infty \frac{1}{n} - \frac{1}{n + 2}

\frac{3}{2}

Solution steps

n = 1 \sum \infty \frac{1}{n} - \frac{1}{n + 2}

Expand telescoping series:

\frac{3}{2}

= \frac{3}{2}

\int \frac{21 x e ^{2 x}}{( 1 + 2 x ) ^{2}} d x

y^{^{'}} = 3 y, y (2) = 4

\frac{d}{d x} (1 + \frac{1}{x} + \frac{1}{x ^{2}})

\int x^{2} + k x + 1 d x

12 (x - \frac{1}{x})^{4}, at x = 2

What is the sum from n=1 to infinity of 1/n-1/(n+2) ?
The sum from n=1 to infinity of 1/n-1/(n+2) is 3/2