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Popular >

y^'=e^{(x+y)}

Solution

y^{^{'}} = e^{(x + y)}

Solution

y = - ln (- e^{x} - c_{1})

Solution steps

y^{'} (x) = e^{(x + y)}

Solve separable ODE:

y = - ln (- e^{x} - c_{1})

y = - ln (- e^{x} - c_{1})

Popular Examples

derivative of h(x)=(5-5x^3)^3+1/(5-5x^3)derivative of

h (x) = (5 - 5 x^{3})^{3} + \frac{1}{5 - 5 x ^{3}}

integral from 0 to pi of 6sin(x)

\int_{0}^{π} 6 sin (x) d x

integral of sec(t)(9sec(t)+7tan(t))

\int sec (t) (9 sec (t) + 7 tan (t)) d t

inverse oflaplace (10)/(s^2+2s+5)inverse laplace

\frac{10}{s ^{2} + 2 s + 5}

integral of 1/(sqrt(x^2-441))

\int \frac{1}{x ^{2} - 441} d x

Frequently Asked Questions (FAQ)

What is the solution for y^'=e^{(x+y)} ?
The solution for y^'=e^{(x+y)} is y=-ln(-e^x-c_{1})