What is (\partial)/(\partial t)(4sin(t)) ?

The answer to (\partial)/(\partial t)(4sin(t)) is 4cos(t)

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(\partial)/(\partial t)(4sin(t))

\frac{\partial}{\partial t} (4 sin (t))

4 cos (t)

Solution steps

\frac{\partial}{\partial t} (4 sin (t))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{\partial}{\partial t} (sin (t))

Apply the common derivative:

\frac{\partial}{\partial t} (sin (t)) = cos (t)

= 4 cos (t)

y = \frac{1}{2} x, y = \frac{1}{25} x^{2}, y = 1

x \to 5 lim (\frac{2 x}{x - 5})

x \to 9 lim (f (x))

\frac{d}{d x} (10 x + 7 x)

f (x) = (4 x + 1)^{2}

What is (\partial)/(\partial t)(4sin(t)) ?
The answer to (\partial)/(\partial t)(4sin(t)) is 4cos(t)