What is the derivative of f(x)=(4x+1)^2 ?

The derivative of f(x)=(4x+1)^2 is 8(4x+1)

What is the first derivative of f(x)=(4x+1)^2 ?

The first derivative of f(x)=(4x+1)^2 is 8(4x+1)

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derivative of

f (x) = (4 x + 1)^{2}

8 (4 x + 1)

Solution steps

\frac{d}{d x} ((4 x + 1)^{2})

Apply the chain rule:

2 (4 x + 1) \frac{d}{d x} (4 x + 1)

= 2 (4 x + 1) \frac{d}{d x} (4 x + 1)

\frac{d}{d x} (4 x + 1) = 4

= 2 (4 x + 1) \cdot 4

Simplify

= 8 (4 x + 1)

\frac{d}{d x} (2 x^{4} - 5 x^{3} + x^{2})

\int_{- 1}^{2} 3 x^{2} + 4 x d x

\int - 4 x + 12 d x

y^{^{'}} = y^{2} x^{3}

3 x^{2} + 12, 4 x + 4, [- 3, 3]

What is the derivative of f(x)=(4x+1)^2 ?
The derivative of f(x)=(4x+1)^2 is 8(4x+1)
What is the first derivative of f(x)=(4x+1)^2 ?
The first derivative of f(x)=(4x+1)^2 is 8(4x+1)