What is the solution for x^{''}-ax=0 ?

The solution for x^{''}-ax=0 is x=c_{1}e^{sqrt(a)t}+c_{2}e^{-sqrt(a)t}

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x^{''}-ax=0

x^{^{''}} - a x = 0

x = c_{1} e^{a t} + c_{2} e^{- a t}

Solution steps

x^{''} (t) - a x (t) = 0

Solve linear ODE:

x = c_{1} e^{a t} + c_{2} e^{- a t}

x = c_{1} e^{a t} + c_{2} e^{- a t}

x \to 0 lim (x^{2} cos (\frac{8}{x}))

y = \frac{3 x - 2}{x}

\frac{d}{d x} (\frac{x ^{2} - 1}{x ^{3} + x + 1})

\frac{\partial}{\partial t} (4 sin (t))

y = \frac{1}{2} x, y = \frac{1}{25} x^{2}, y = 1

What is the solution for x^{''}-ax=0 ?
The solution for x^{''}-ax=0 is x=c_{1}e^{sqrt(a)t}+c_{2}e^{-sqrt(a)t}