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Popular >

integral from 0 to 1 of-x+2

Solution

\int_{0}^{1} - x + 2 d x

Solution

\frac{3}{2}

+1

Solution steps

\int_{0}^{1} - x + 2 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{0}^{1} x d x + \int_{0}^{1} 2 d x

\int_{0}^{1} x d x = \frac{1}{2}

\int_{0}^{1} 2 d x = 2

= - \frac{1}{2} + 2

Simplify

- \frac{1}{2} + 2 : \frac{3}{2}

= \frac{3}{2}

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\frac{- 40 x - 80}{x ^{2} + 3 x + 1}

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(\frac{1}{4}) y^{^{''}} + y^{^{'}} + y = x^{2} - 2 x

(dx)/(sqrt(1-x^2))=(dy)/(sqrt(1-y^2))

\frac{d x}{1 - x ^{2}} = \frac{d y}{1 - y ^{2}}

integral of (7x)/((x^2+7)^2)

\int \frac{7 x}{( x ^{2} + 7 ) ^{2}} d x

Frequently Asked Questions (FAQ)

What is the integral from 0 to 1 of-x+2 ?
The integral from 0 to 1 of-x+2 is 3/2