What is the sum from n=3 to infinity}((-1)^{n+1 of)/(n!) ?

The sum from n=3 to infinity}((-1)^{n+1 of)/(n!) is converges

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sum from n=3 to infinity}((-1)^{n+1 of)/(n!)

n = 3 \sum \infty \frac{( - 1 ) ^{n + 1}}{n !}

converges

Solution steps

n = 3 \sum \infty \frac{( - 1 ) ^{n + 1}}{n !}

Apply Alternating Series Test:

converges

= converges

\int e^{(x^{2})} d x

\int 3 e^{x^{2}} x d x

x \to 0 + lim (\frac{7 x}{∣ x ∣})

t^{2} \frac{d y}{d t} + t y = 5

\int 3 x + 4 d x

What is the sum from n=3 to infinity}((-1)^{n+1 of)/(n!) ?
The sum from n=3 to infinity}((-1)^{n+1 of)/(n!) is converges