{
"query": {
"display": "$$\\int\\:e^{-x}\\left(9+e^{-x}\\right)dx$$",
"symbolab_question": "BIG_OPERATOR#\\int e^{-x}(9+e^{-x})dx"
},
"solution": {
"level": "PERFORMED",
"subject": "Calculus",
"topic": "Integrals",
"subTopic": "Indefinite Integrals",
"default": "-\\frac{(9+e^{-x})^{2}}{2}+C",
"meta": {
"showVerify": true
}
},
"steps": {
"type": "interim",
"title": "$$\\int\\:e^{-x}\\left(9+e^{-x}\\right)dx=-\\frac{\\left(9+e^{-x}\\right)^{2}}{2}+C$$",
"input": "\\int\\:e^{-x}\\left(9+e^{-x}\\right)dx",
"steps": [
{
"type": "interim",
"title": "Apply u-substitution",
"input": "\\int\\:e^{-x}\\left(9+e^{-x}\\right)dx",
"steps": [
{
"type": "definition",
"title": "Integral Substitution definition",
"text": "$$\\int\\:f\\left(g\\left(x\\right)\\right)\\cdot\\:g'\\left(x\\right)dx=\\int\\:f\\left(u\\right)du,\\:\\quad\\:u=g\\left(x\\right)$$",
"secondary": [
"Substitute: $$u=9+e^{-x}$$"
]
},
{
"type": "interim",
"title": "$$\\frac{du}{dx}=-e^{-x}$$",
"input": "\\frac{d}{dx}\\left(9+e^{-x}\\right)",
"steps": [
{
"type": "step",
"primary": "Apply the Sum/Difference Rule: $$\\left(f{\\pm}g\\right)'=f'{\\pm}g'$$",
"result": "=\\frac{d}{dx}\\left(9\\right)+\\frac{d}{dx}\\left(e^{-x}\\right)"
},
{
"type": "interim",
"title": "$$\\frac{d}{dx}\\left(9\\right)=0$$",
"input": "\\frac{d}{dx}\\left(9\\right)",
"steps": [
{
"type": "step",
"primary": "Derivative of a constant: $$\\frac{d}{dx}\\left({a}\\right)=0$$",
"result": "=0"
}
],
"meta": {
"solvingClass": "Derivatives",
"interimType": "Derivatives",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s79Kg+idP5vLVrjUll6eMdYvTYt8V2vaKd9AkmdqaaXItJ8Vk6wvKjVnTtwWT18bQnz7FeFrf3rcM8IZlDz2c0dm5O2bEw0Ql6ne7k1AUriTsdQFf8ULyNiNWh+aczQhPx"
}
},
{
"type": "interim",
"title": "$$\\frac{d}{dx}\\left(e^{-x}\\right)=-e^{-x}$$",
"input": "\\frac{d}{dx}\\left(e^{-x}\\right)",
"steps": [
{
"type": "interim",
"title": "Apply the chain rule:$${\\quad}e^{-x}\\frac{d}{dx}\\left(-x\\right)$$",
"input": "\\frac{d}{dx}\\left(e^{-x}\\right)",
"result": "=e^{-x}\\frac{d}{dx}\\left(-x\\right)",
"steps": [
{
"type": "step",
"primary": "Apply the chain rule: $$\\frac{df\\left(u\\right)}{dx}=\\frac{df}{du}\\cdot\\frac{du}{dx}$$",
"secondary": [
"$$f=e^{u},\\:\\:u=-x$$"
],
"result": "=\\frac{d}{du}\\left(e^{u}\\right)\\frac{d}{dx}\\left(-x\\right)",
"meta": {
"practiceLink": "/practice/derivatives-practice#area=main&subtopic=Chain%20Rule",
"practiceTopic": "Chain Rule"
}
},
{
"type": "interim",
"title": "$$\\frac{d}{du}\\left(e^{u}\\right)=e^{u}$$",
"input": "\\frac{d}{du}\\left(e^{u}\\right)",
"steps": [
{
"type": "step",
"primary": "Apply the common derivative: $$\\frac{d}{du}\\left(e^{u}\\right)=e^{u}$$",
"result": "=e^{u}"
}
],
"meta": {
"solvingClass": "Derivatives",
"interimType": "Derivatives",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s79Kg+idP5vLVrjUll6eMdYqCr3EWRZw3L4+rHTTdVG0Ok3hxk9aCfAWodBRxXgUexwx+RE9MtjN5hKMwTI7fffj/L0MoYg+CUn6oyL3EO7YrHahlpzKGY893KZ4T4i4Tv3RCXWsqiNx7T9zOhL5sYfw=="
}
},
{
"type": "step",
"result": "=e^{u}\\frac{d}{dx}\\left(-x\\right)"
},
{
"type": "step",
"primary": "Substitute back $$u=-x$$",
"result": "=e^{-x}\\frac{d}{dx}\\left(-x\\right)"
}
],
"meta": {
"interimType": "Derivative Chain Rule 0Eq",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s79Kg+idP5vLVrjUll6eMdYmBepZeKV8bVrdHbYZEMXtOTdaV09PMxEKZ9FieghTFwc6p4sNpoW3XPzo2W3Ux6aosjLe8tD9HbrkG8vq6q9jiWR6DAIfSwNblE3ziU9D9b9KdAd3NQb43TJHJRafLwY/C30sSftAIFS6Qkpy19IkrNs0uRhmwmWtV92tk+c/8Zu/mDTHcAziAiYeNOzjloJg=="
}
},
{
"type": "interim",
"title": "$$\\frac{d}{dx}\\left(-x\\right)=-1$$",
"input": "\\frac{d}{dx}\\left(-x\\right)",
"steps": [
{
"type": "step",
"primary": "Take the constant out: $$\\left(a{\\cdot}f\\right)'=a{\\cdot}f'$$",
"result": "=-\\frac{dx}{dx}"
},
{
"type": "step",
"primary": "Apply the common derivative: $$\\frac{dx}{dx}=1$$",
"result": "=-1"
}
],
"meta": {
"solvingClass": "Derivatives",
"interimType": "Derivatives",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s79Kg+idP5vLVrjUll6eMdYlIFiSG67zLdq9NRnof0E3fZGku9zFkxwe1dTH8vycb9+906N5fPsfVzu/TlcIEC4c1bIZxfodm3UsZcfZAZr4tZsYzC8RJ0SqIyNjewPF2dJLd1ohke2Wgml78++2zI0g=="
}
},
{
"type": "step",
"result": "=e^{-x}\\left(-1\\right)"
},
{
"type": "step",
"primary": "Simplify",
"result": "=-e^{-x}",
"meta": {
"solvingClass": "Solver"
}
}
],
"meta": {
"solvingClass": "Derivatives",
"interimType": "Derivatives"
}
},
{
"type": "step",
"result": "=0-e^{-x}"
},
{
"type": "step",
"primary": "Simplify",
"result": "=-e^{-x}",
"meta": {
"solvingClass": "Solver"
}
}
],
"meta": {
"solvingClass": "Derivatives",
"interimType": "Derivatives"
}
},
{
"type": "step",
"primary": "$$\\quad\\Rightarrow\\:du=-e^{-x}dx$$"
},
{
"type": "step",
"primary": "$$\\quad\\Rightarrow\\:dx=\\left(-e^{x}\\right)du$$"
},
{
"type": "step",
"result": "=\\int\\:e^{-x}u\\left(-e^{x}\\right)du"
},
{
"type": "interim",
"title": "Simplify $$e^{-x}u\\left(-e^{x}\\right):{\\quad}-u$$",
"input": "e^{-x}u\\left(-e^{x}\\right)",
"steps": [
{
"type": "step",
"primary": "Remove parentheses: $$\\left(-a\\right)=-a$$",
"result": "=-e^{-x}ue^{x}"
},
{
"type": "step",
"primary": "Apply exponent rule: $$a^b\\cdot\\:a^c=a^{b+c}$$",
"secondary": [
"$$e^{-x}e^{x}=\\:e^{-x+x}$$"
],
"result": "=-ue^{-x+x}",
"meta": {
"practiceLink": "/practice/exponent-practice",
"practiceTopic": "Expand FOIL"
}
},
{
"type": "step",
"primary": "Add similar elements: $$-x+x=0$$",
"result": "=-ue^{0}"
},
{
"type": "step",
"primary": "Apply rule $$a^{0}=1,\\:a\\ne\\:0$$",
"result": "=-1\\cdot\\:u"
},
{
"type": "step",
"primary": "Multiply: $$u\\cdot\\:1=u$$",
"result": "=-u"
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Algebraic Manipulation Simplify Title 1Eq"
}
},
{
"type": "step",
"result": "=\\int\\:-udu"
}
],
"meta": {
"interimType": "Integral U Substitution 1Eq",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s7l7+Hp9GxvB/5I+4/5L7s76lg3ebd/YWy6iKCI/g2wi+r+0zX0wqSmAVtc7NV8L0A/6umhM84nJGixAkjaEU36WyJTZPfTsR1UcTUz/dkJr0tLoVIh4O4ahvnBYDckgF7dnTglfS5p6JXgzyqnzCTNn0OUPyXQtFGiOjmEr/XNM7GozyzE+voogmEOxXArER7JLd1ohke2Wgml78++2zI0g=="
}
},
{
"type": "step",
"result": "=\\int\\:-udu"
},
{
"type": "step",
"primary": "Take the constant out: $$\\int{a\\cdot{f\\left(x\\right)}dx}=a\\cdot\\int{f\\left(x\\right)dx}$$",
"result": "=-\\int\\:udu"
},
{
"type": "interim",
"title": "Apply the Power Rule",
"input": "\\int\\:udu",
"result": "=-\\frac{u^{2}}{2}",
"steps": [
{
"type": "step",
"primary": "Apply the Power Rule: $$\\int{x^{a}}dx=\\frac{x^{a+1}}{a+1},\\:\\quad\\:a\\neq{-1}$$",
"result": "=\\frac{u^{1+1}}{1+1}"
},
{
"type": "interim",
"title": "Simplify $$\\frac{u^{1+1}}{1+1}:{\\quad}\\frac{u^{2}}{2}$$",
"input": "\\frac{u^{1+1}}{1+1}",
"steps": [
{
"type": "step",
"primary": "Add the numbers: $$1+1=2$$",
"result": "=\\frac{u^{2}}{2}"
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Algebraic Manipulation Simplify Title 1Eq"
}
},
{
"type": "step",
"result": "=\\frac{u^{2}}{2}"
}
],
"meta": {
"interimType": "Power Rule Top 0Eq",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s7l7+Hp9GxvB/5I+4/5L7s77irOeniMfrJKKN+TrhAcvL/JyKXuO90NgYuEtRnVFUoQEgTxsQDcbkC7lns/WqbpAUgTzPSdH5PWV4NCtvwjA7/YrZ1UCh4L70vx5eDNyDLTeQKHeh69S6dnv9vSoUoFEMybLZHp2MhZ1cw+jOu7RuDCZKz/+DESbePVmsYY2Aq"
}
},
{
"type": "step",
"primary": "Substitute back $$u=9+e^{-x}$$",
"result": "=-\\frac{\\left(9+e^{-x}\\right)^{2}}{2}"
},
{
"type": "step",
"primary": "Add a constant to the solution",
"result": "=-\\frac{\\left(9+e^{-x}\\right)^{2}}{2}+C",
"meta": {
"title": {
"extension": "If $$\\frac{dF\\left(x\\right)}{dx}=f\\left(x\\right)$$ then $$\\int{f\\left(x\\right)}dx=F\\left(x\\right)+C$$"
}
}
}
],
"meta": {
"solvingClass": "Integrals",
"practiceLink": "/practice/integration-practice#area=main&subtopic=Substitution",
"practiceTopic": "Integral Substitution"
}
},
"plot_output": {
"meta": {
"plotInfo": {
"variable": "x",
"plotRequest": "y=-\\frac{(9+e^{-x})^{2}}{2}+C"
},
"showViewLarger": true
}
},
"meta": {
"showVerify": true
}
}
Solution
Solution
Solution steps
Apply u-substitution
Take the constant out:
Apply the Power Rule
Substitute back
Add a constant to the solution
Graph
Popular Examples
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Frequently Asked Questions (FAQ)
What is the integral of e^{-x}(9+e^{-x}) ?
The integral of e^{-x}(9+e^{-x}) is -((9+e^{-x})^2)/2+C