What is the derivative of f(x)=sqrt(x+13) ?

The derivative of f(x)=sqrt(x+13) is 1/(2sqrt(x+13))

What is the first derivative of f(x)=sqrt(x+13) ?

The first derivative of f(x)=sqrt(x+13) is 1/(2sqrt(x+13))

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derivative of

f (x) = x + 13

\frac{1}{2 x + 13}

Solution steps

\frac{d}{d x} (x + 13)

Apply the chain rule:

\frac{1}{2 x + 13} \frac{d}{d x} (x + 13)

= \frac{1}{2 x + 13} \frac{d}{d x} (x + 13)

\frac{d}{d x} (x + 13) = 1

= \frac{1}{2 x + 13} \cdot 1

Simplify

= \frac{1}{2 x + 13}

x y^{^{'}} - y = - 2 x^{2} - 2 x + 1

\frac{\partial}{\partial z} (x y^{2} e^{y})

\frac{d}{d x} y = (3 - e^{- x})^{2}

\int \frac{1}{4 x - 10} d x

\frac{\partial}{\partial x} (sin^{2} (θ))

What is the derivative of f(x)=sqrt(x+13) ?
The derivative of f(x)=sqrt(x+13) is 1/(2sqrt(x+13))
What is the first derivative of f(x)=sqrt(x+13) ?
The first derivative of f(x)=sqrt(x+13) is 1/(2sqrt(x+13))