derivative f(r)=sqrt(r)+\sqrt[7]{r}

Lösung

ableitung von

f (r) = r + 7 r

\frac{1}{2 r} + \frac{1}{7 r ^{\frac{6}{7}}}

Schritte zur Lösung

\frac{d}{d r} (r + 7 r)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d r} (r) + \frac{d}{d r} (7 r)

\frac{d}{d r} (r) = \frac{1}{2 r}

\frac{d}{d r} (7 r) = \frac{1}{7 r ^{\frac{6}{7}}}

= \frac{1}{2 r} + \frac{1}{7 r ^{\frac{6}{7}}}

\int (2 x e^{- 3 x}) d x

y^{^{'}} + 2 sin (2 x) y = 2 sin (2 x), y (\frac{π}{2}) = 3

h \to 0 lim ((- 4)^{2} + 2 (- 4))

\int \frac{x ^{2}}{21 + 4 x - x ^{2}} d x

in v erse l a pl a ce \frac{( s + 9 )}{( s ^{2} + 6 s + 34 )}