What is the solution for y^'=cos^2(y)ln(x) ?

The solution for y^'=cos^2(y)ln(x) is y=arctan(xln(x)-x+c_{1})+pin

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y^'=cos^2(y)ln(x)

y^{^{'}} = cos^{2} (y) ln (x)

y = arctan (x ln (x) - x + c_{1}) + πn

Solution steps

y^{'} (x) = cos^{2} (y) ln (x)

Solve separable ODE:

y = arctan (x ln (x) - x + c_{1}) + πn

y = arctan (x ln (x) - x + c_{1}) + πn

\frac{\partial}{\partial x} (e^{5 x} sin (5 y))

\frac{x ^{2} - 1}{x ^{2} + x + 1}

y = - \frac{2}{x ^{2}}

2 sin (4 π (x + \frac{1}{8}))

\int \frac{x + 1}{x - 1} d x

What is the solution for y^'=cos^2(y)ln(x) ?
The solution for y^'=cos^2(y)ln(x) is y=arctan(xln(x)-x+c_{1})+pin