What is longdivision (x^2-1)/(x^2+x+1) ?

The solution to longdivision (x^2-1)/(x^2+x+1) is 1+(-x-2)/(x^2+x+1)

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longdivision (x^2-1)/(x^2+x+1)

long division

\frac{x ^{2} - 1}{x ^{2} + x + 1}

1 + \frac{- x - 2}{x ^{2} + x + 1}

Solution steps

\frac{x ^{2} - 1}{x ^{2} + x + 1}

Divide

\frac{x ^{2} - 1}{x ^{2} + x + 1} : \frac{x ^{2} - 1}{x ^{2} + x + 1} = 1 + \frac{- x - 2}{x ^{2} + x + 1}

= 1 + \frac{- x - 2}{x ^{2} + x + 1}

y = - \frac{2}{x ^{2}}

2 sin (4 π (x + \frac{1}{8}))

\int \frac{x + 1}{x - 1} d x

x \to - 1 lim (8 x^{3})

4 x^{2}, x^{4} - 6 x^{2}, [- 3, 3]

What is longdivision (x^2-1)/(x^2+x+1) ?
The solution to longdivision (x^2-1)/(x^2+x+1) is 1+(-x-2)/(x^2+x+1)