y^'=5x

Lösung

y^{^{'}} = 5 x

y = \frac{5 x ^{2}}{2} + c_{1}

Schritte zur Lösung

y^{'} (x) = 5 x

Wenn

f^{^{'}} (x) = g (x)

dann

f (x) = \int g (x) d x

y = \int 5 x d x

\int 5 x d x = \frac{5 x ^{2}}{2} + c_{1}

y = \frac{5 x ^{2}}{2} + c_{1}

\int (\frac{3}{x ^{4}} + 2 - \frac{3}{x ^{2}}) d x

\int_{1}^{\infty} x e^{- 6 x} d x

\frac{d}{d x} (\frac{4 x - 7}{x - 2})

p a r i t y x^{4} sin (x) tan (x)

t an g e n t f (x) = 5 + 5 x^{2} - 2 x^{3}, at x = 1