derivative of (x^2+3x-2^4)

Lösung

\frac{d}{d x} ((x^{2} + 3 x - 2)^{4})

4 (x^{2} + 3 x - 2)^{3} (2 x + 3)

Schritte zur Lösung

\frac{d}{d x} ((x^{2} + 3 x - 2)^{4})

Wende die Kettenregel an:

4 (x^{2} + 3 x - 2)^{3} \frac{d}{d x} (x^{2} + 3 x - 2)

= 4 (x^{2} + 3 x - 2)^{3} \frac{d}{d x} (x^{2} + 3 x - 2)

\frac{d}{d x} (x^{2} + 3 x - 2) = 2 x + 3

= 4 (x^{2} + 3 x - 2)^{3} (2 x + 3)

x \to 0 lim (\frac{tan ( 6 x )}{sin ( 5 x )})

\frac{\partial}{\partial x} (x^{2} + 16 x w + 64 w^{2})

x \to 3 - lim (\frac{2 x + 1}{x - 3})

x \to 0 - lim (\frac{4}{5 x ^{\frac{1}{3}}})

\int \frac{5}{2} d x