What is the limit as x approaches 0-of 4/(5x^{1/3)} ?

The limit as x approaches 0-of 4/(5x^{1/3)} is -infinity

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limit as x approaches 0-of 4/(5x^{1/3)}

x \to 0 - lim (\frac{4}{5 x ^{\frac{1}{3}}})

- \infty

Solution steps

x \to 0 - lim (\frac{4}{5 x ^{\frac{1}{3}}})

For

x

approaching

0

from the left

, x < 0 \Rightarrow 5 x^{\frac{1}{3}} < 0

The denominator is a negative quantity approaching 0 from the left

= - \infty

\int \frac{5}{2} d x

\int_{1}^{\infty} 12 e^{- 4 x} d x

(\frac{t ^{3}}{t ^{8} + 7})^{2}

\int (x + 1) ln (2 x + 4) d x

\frac{d}{d x} ((\frac{1}{x ^{2}} - \frac{3}{x ^{4}}) (x + 7 x^{3}))

What is the limit as x approaches 0-of 4/(5x^{1/3)} ?
The limit as x approaches 0-of 4/(5x^{1/3)} is -infinity