What is the first derivative of 2ax ?

The first derivative of 2ax is 2a

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derivative of 2ax

\frac{d}{d x} (2 a x)

2 a

Solution steps

\frac{d}{d x} (2 a x)

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 a \frac{d x}{d x}

Apply the common derivative:

\frac{d x}{d x} = 1

= 2 a \cdot 1

Simplify

= 2 a

\int (x + 2 y) d y

θ^{^{''}} = 3 θ

\int (2 u + 1)^{2} d u

f (x) = \frac{x}{1 + x ^{2}}, at x = 3

5 x^{2} + 3 x^{4}