integral from 1 to 4 of 7/(x^2)

Lösung

\int_{1}^{4} \frac{7}{x ^{2}} d x

\frac{21}{4}

Dezimale

5.25

Schritte zur Lösung

\int_{1}^{4} \frac{7}{x ^{2}} d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 7 \cdot \int_{1}^{4} \frac{1}{x ^{2}} d x

Wende die Potenzregel an

= 7 [- \frac{1}{x}]_{1}^{4}

Berechne die Grenzen:

\frac{3}{4}

= 7 \cdot \frac{3}{4}

Vereinfache

= \frac{21}{4}

(9 x + 3) + (9 y - 9) y^{^{'}} = 0

\int_{0}^{3} (x + 9 - x^{2}) d x

\int_{1}^{2} cos (x^{2}) d x

\frac{\partial}{\partial y} (x^{2} + x y)

\frac{d}{d x} (\frac{9 x}{x})