(\partial)/(\partial y)(x^2+xy)

解答

\frac{\partial}{\partial y} (x^{2} + x y)

x

求解步骤

\frac{\partial}{\partial y} (x^{2} + x y)

将

x

视为常数

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (x^{2}) + \frac{\partial}{\partial y} (x y)

\frac{\partial}{\partial y} (x^{2}) = 0

\frac{\partial}{\partial y} (x y) = x

= 0 + x

化简

= x

\frac{d}{d x} (\frac{9 x}{x})

\int \frac{2 - x}{x} d x

\frac{d}{d x} (cos^{2} (1 - x^{2}))

d er i v a t i v e \frac{1 - 4 t}{3 + t}

\int \frac{( 2 z - 1 )}{2 z ^{2} - 6 z + 5} d z