What is the integral of cos(x)(3+4sin^2(x)) ?

The integral of cos(x)(3+4sin^2(x)) is 3sin(x)+(4sin^3(x))/3+C

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integral of cos(x)(3+4sin^2(x))

\int cos (x) (3 + 4 sin^{2} (x)) d x

3 sin (x) + \frac{4 sin ^{3} ( x )}{3} + C

Solution steps

\int cos (x) (3 + 4 sin^{2} (x)) d x

Apply u-substitution

: \int 3 + 4 u^{2} d u

= \int 3 + 4 u^{2} d u

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 3 d u + \int 4 u^{2} d u

\int 3 d u = 3 u

\int 4 u^{2} d u = \frac{4 u ^{3}}{3}

= 3 u + \frac{4 u ^{3}}{3}

Substitute back

u = sin (x)

= 3 sin (x) + \frac{4 sin ^{3} ( x )}{3}

Add a constant to the solution

= 3 sin (x) + \frac{4 sin ^{3} ( x )}{3} + C

\frac{d}{d x} ((3 x - 2 y)^{2} - (2 x - 3 y)^{2})

\frac{7 ( 1 - sin ( x ) )}{2 cos ( x )}

\int_{0}^{2 π} sin (2 x) d x

\int \frac{e ^{2 x + 1}}{2} d x

ln (x^{2} + y^{2})

What is the integral of cos(x)(3+4sin^2(x)) ?
The integral of cos(x)(3+4sin^2(x)) is 3sin(x)+(4sin^3(x))/3+C