What is laplacetransform sin(5t-10) ?

The answer to laplacetransform sin(5t-10) is (-sin(10)s+5cos(10))/(s^2+25)

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laplacetransform sin(5t-10)

laplace transform

sin (5 t - 10)

\frac{- sin ( 10 ) s + 5 cos ( 10 )}{s ^{2} + 25}

Solution steps

L {sin (5 t - 10)}

Use Laplace Transform table:

L {sin (a t + b)} = \frac{s \cdot sin ( b ) + a \cdot cos ( b )}{s ^{2} + a ^{2}}

L {sin (5 t - 10)} = \frac{s sin ( - 10 ) + 5 cos ( - 10 )}{s ^{2} + 5 ^{2}}

= \frac{s sin ( - 10 ) + 5 cos ( - 10 )}{s ^{2} + 5 ^{2}}

= \frac{- sin ( 10 ) s + 5 cos ( 10 )}{s ^{2} + 25}

\int_{2}^{5} x^{4} d x

(2 x^{2} + 5) (4 x - 1)

y^{^{'}} + 4 y = x e^{- 4 x}

\int_{- 1}^{2} x e^{x y} d y

\frac{d}{d x} (1 + 2 e^{x} - 3 x)

What is laplacetransform sin(5t-10) ?
The answer to laplacetransform sin(5t-10) is (-sin(10)s+5cos(10))/(s^2+25)