What is the derivative of (2x^2+5)(4x-1) ?

The derivative of (2x^2+5)(4x-1) is 24x^2-4x+20

What is the first derivative of (2x^2+5)(4x-1) ?

The first derivative of (2x^2+5)(4x-1) is 24x^2-4x+20

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derivative of

(2 x^{2} + 5) (4 x - 1)

24 x^{2} - 4 x + 20

Solution steps

\frac{d}{d x} ((2 x^{2} + 5) (4 x - 1))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = 2 x^{2} + 5, g = 4 x - 1

= \frac{d}{d x} (2 x^{2} + 5) (4 x - 1) + \frac{d}{d x} (4 x - 1) (2 x^{2} + 5)

\frac{d}{d x} (2 x^{2} + 5) = 4 x

\frac{d}{d x} (4 x - 1) = 4

= 4 x (4 x - 1) + 4 (2 x^{2} + 5)

Simplify

4 x (4 x - 1) + 4 (2 x^{2} + 5) : 24 x^{2} - 4 x + 20

= 24 x^{2} - 4 x + 20

y^{^{'}} + 4 y = x e^{- 4 x}

\int_{- 1}^{2} x e^{x y} d y

\frac{d}{d x} (1 + 2 e^{x} - 3 x)

\int 5 x^{7} d x

\frac{d}{d x} (x^{2} + z (x) (x)^{2})

What is the derivative of (2x^2+5)(4x-1) ?
The derivative of (2x^2+5)(4x-1) is 24x^2-4x+20
What is the first derivative of (2x^2+5)(4x-1) ?
The first derivative of (2x^2+5)(4x-1) is 24x^2-4x+20