What is the tangent of f(x)= 1/(x-2),\at x=6 ?

The tangent of f(x)= 1/(x-2),\at x=6 is y=-1/16 x+5/8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

tangent of f(x)= 1/(x-2),\at x=6

tangent of

f (x) = \frac{1}{x - 2}, at x = 6

y = - \frac{1}{16} x + \frac{5}{8}

Solution steps

Find the tangent point:

(6, \frac{1}{4})

Find the slope of

f (x) = \frac{1}{x - 2} : \frac{df ( x )}{d x} = - \frac{1}{( x - 2 ) ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{1}{16}

Find the line with slope m=

- \frac{1}{16}

and passing through

(6, \frac{1}{4}) : y = - \frac{1}{16} x + \frac{5}{8}

y = - \frac{1}{16} x + \frac{5}{8}

What is the tangent of f(x)= 1/(x-2),\at x=6 ?
The tangent of f(x)= 1/(x-2),\at x=6 is y=-1/16 x+5/8