derivative y=x^2+2x-2

Lösung

ableitung von

y = x^{2} + 2 x - 2

2 x + 2

Schritte zur Lösung

\frac{d}{d x} (x^{2} + 2 x - 2)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (2 x) - \frac{d}{d x} (2)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (2) = 0

= 2 x + 2 - 0

Vereinfache

= 2 x + 2

y^{^{'}} = e^{9 y - x}

t an g e n t f (x) = x^{3}, at x = - 5

x \to 0 lim (1 - cos (3 x))

x \to \infty lim (lo g_{2} (lo g_{2} (x) - 1))

\int_{0}^{\frac{π}{2}} sin^{5} (x) d x