y^'=e^{9y-x}

Lösung

y^{^{'}} = e^{9 y - x}

y = - \frac{ln ( 9 e ^{- x} - c _{1} )}{9}

Schritte zur Lösung

y^{'} (x) = e^{9 y - x}

Solve separable ODE:

y = - \frac{ln ( 9 e ^{- x} - c _{1} )}{9}

y = - \frac{ln ( 9 e ^{- x} - c _{1} )}{9}

t an g e n t f (x) = x^{3}, at x = - 5

x \to 0 lim (1 - cos (3 x))

x \to \infty lim (lo g_{2} (lo g_{2} (x) - 1))

\int_{0}^{\frac{π}{2}} sin^{5} (x) d x

\int_{0}^{2} 8000 t e^{- 0.6 t} d t