What is (\partial)/(\partial x)(-8(x+y+z)^2) ?

The answer to (\partial)/(\partial x)(-8(x+y+z)^2) is -16(x+y+z)

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(\partial)/(\partial x)(-8(x+y+z)^2)

\frac{\partial}{\partial x} (- 8 (x + y + z)^{2})

- 16 (x + y + z)

Solution steps

\frac{\partial}{\partial x} (- 8 (x + y + z)^{2})

Treat

y, z

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 8 \frac{\partial}{\partial x} ((x + y + z)^{2})

Apply the chain rule:

2 (x + y + z) \frac{\partial}{\partial x} (x + y + z)

= 2 (x + y + z) \frac{\partial}{\partial x} (x + y + z)

\frac{\partial}{\partial x} (x + y + z) = 1

= - 8 \cdot 2 (x + y + z) \cdot 1

Simplify

= - 16 (x + y + z)

\int \frac{arcsin ( x )}{( 1 - x ^{2} ) ^{\frac{1}{2}}} d x

x \to 0 lim (x^{15 x})

\int \frac{x ^{3}}{6 - x ^{4}} d x

\frac{6 u ^{2}}{( u ^{2} + u ) ^{3}}

[δ (t + 1)]

What is (\partial)/(\partial x)(-8(x+y+z)^2) ?
The answer to (\partial)/(\partial x)(-8(x+y+z)^2) is -16(x+y+z)