{
"query": {
"display": "$$\\frac{\\partial\\:}{\\partial\\:x}\\left(-8\\left(x+y+z\\right)^{2}\\right)$$",
"symbolab_question": "DERIVATIVE#\\frac{\\partial }{\\partial x}(-8(x+y+z)^{2})"
},
"solution": {
"level": "PERFORMED",
"subject": "Calculus",
"topic": "Derivatives",
"subTopic": "Partial Derivatives",
"default": "-16(x+y+z)",
"meta": {
"showVerify": true
}
},
"steps": {
"type": "interim",
"title": "$$\\frac{\\partial\\:}{\\partial\\:x}\\left(-8\\left(x+y+z\\right)^{2}\\right)=-16\\left(x+y+z\\right)$$",
"input": "\\frac{\\partial\\:}{\\partial\\:x}\\left(-8\\left(x+y+z\\right)^{2}\\right)",
"steps": [
{
"type": "step",
"primary": "Treat $$y,\\:z\\:$$as constants"
},
{
"type": "step",
"primary": "Take the constant out: $$\\left(a{\\cdot}f\\right)'=a{\\cdot}f'$$",
"result": "=-8\\frac{\\partial\\:}{\\partial\\:x}\\left(\\left(x+y+z\\right)^{2}\\right)"
},
{
"type": "interim",
"title": "Apply the chain rule:$${\\quad}2\\left(x+y+z\\right)\\frac{\\partial\\:}{\\partial\\:x}\\left(x+y+z\\right)$$",
"input": "\\frac{\\partial\\:}{\\partial\\:x}\\left(\\left(x+y+z\\right)^{2}\\right)",
"result": "=2\\left(x+y+z\\right)\\frac{\\partial\\:}{\\partial\\:x}\\left(x+y+z\\right)",
"steps": [
{
"type": "step",
"primary": "Apply the chain rule: $$\\frac{df\\left(u\\right)}{dx}=\\frac{df}{du}\\cdot\\frac{du}{dx}$$",
"secondary": [
"$$f=u^{2},\\:\\:u=\\left(x+y+z\\right)$$"
],
"result": "=\\frac{\\partial\\:}{\\partial\\:u}\\left(u^{2}\\right)\\frac{\\partial\\:}{\\partial\\:x}\\left(\\left(x+y+z\\right)\\right)",
"meta": {
"practiceLink": "/practice/derivatives-practice#area=main&subtopic=Chain%20Rule",
"practiceTopic": "Chain Rule"
}
},
{
"type": "interim",
"title": "$$\\frac{\\partial\\:}{\\partial\\:u}\\left(u^{2}\\right)=2u$$",
"input": "\\frac{\\partial\\:}{\\partial\\:u}\\left(u^{2}\\right)",
"steps": [
{
"type": "step",
"primary": "Apply the Power Rule: $$\\frac{d}{dx}\\left(x^a\\right)=a{\\cdot}x^{a-1}$$",
"result": "=2u^{2-1}",
"meta": {
"practiceLink": "/practice/derivatives-practice#area=main&subtopic=Power%20Rule",
"practiceTopic": "Power Rule"
}
},
{
"type": "step",
"primary": "Simplify",
"result": "=2u",
"meta": {
"solvingClass": "Solver"
}
}
],
"meta": {
"solvingClass": "Derivatives",
"interimType": "Derivatives",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s79Kg+idP5vLVrjUll6eMdYp9ApVx6pk97jrrFSzJxOAlk+sT8PdKjX3IOZNAv4DdeHI5S0StY1FdtOqqOPr0Te9NVo9MACLuml/Lpxq9I00hkS3dlcCKpQTQcheuut7Mkm+hmRJA1ZPgdMDAPJn089tuZ+dDFI37AdjP7AT1e0ClUFJjxir5UHSHqDvA4SbOG"
}
},
{
"type": "step",
"result": "=2u\\frac{\\partial\\:}{\\partial\\:x}\\left(\\left(x+y+z\\right)\\right)"
},
{
"type": "step",
"primary": "Substitute back $$u=\\left(x+y+z\\right)$$",
"result": "=2\\left(x+y+z\\right)\\frac{\\partial\\:}{\\partial\\:x}\\left(x+y+z\\right)"
}
],
"meta": {
"interimType": "Derivative Chain Rule 0Eq",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s79Kg+idP5vLVrjUll6eMdYp9ApVx6pk97jrrFSzJxOAkVvc1gV0n/3vctIfdCga7BWAV6Hot8PZpHVZcSNnzfwTomiybi+UcYLpl9IDb09fW3GAbya69FFUWYc3u5k63a8II003/3BXxjyiM8pLII8RskcLwm+2BGpNoxeLb6kaibgYg8/1iDoZts7IrJa3FQZPPVCWHJslu8Aaaa8flnHnql8XXPq6bNQlMm+36iNhmvvtFFwhWg0YwYRghPBBH5pEPyZ7DOOfo++3arnOi9/A=="
}
},
{
"type": "interim",
"title": "$$\\frac{\\partial\\:}{\\partial\\:x}\\left(x+y+z\\right)=1$$",
"input": "\\frac{\\partial\\:}{\\partial\\:x}\\left(x+y+z\\right)",
"steps": [
{
"type": "step",
"primary": "Apply the Sum/Difference Rule: $$\\left(f{\\pm}g\\right)'=f'{\\pm}g'$$",
"result": "=\\frac{\\partial\\:}{\\partial\\:x}\\left(x\\right)+\\frac{\\partial\\:}{\\partial\\:x}\\left(y\\right)+\\frac{\\partial\\:}{\\partial\\:x}\\left(z\\right)"
},
{
"type": "interim",
"title": "$$\\frac{\\partial\\:}{\\partial\\:x}\\left(x\\right)=1$$",
"input": "\\frac{\\partial\\:}{\\partial\\:x}\\left(x\\right)",
"steps": [
{
"type": "step",
"primary": "Apply the common derivative: $$\\frac{\\partial\\:}{\\partial\\:x}\\left(x\\right)=1$$",
"result": "=1"
}
],
"meta": {
"solvingClass": "Derivatives",
"interimType": "Derivatives",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s79Kg+idP5vLVrjUll6eMdYp9ApVx6pk97jrrFSzJxOAmuHQGTAre0/umYO3/E+LF4lyEB4JYjIUjkjbDZ4tfSJ+yeROYBotscHIZETI6FSe7NWyGcX6HZt1LGXH2QGa+Ln0ClXHqmT3uOusVLMnE4CdhSH/V18j9Kf/3yKXdVwr8kt3WiGR7ZaCaXvz77bMjS"
}
},
{
"type": "interim",
"title": "$$\\frac{\\partial\\:}{\\partial\\:x}\\left(y\\right)=0$$",
"input": "\\frac{\\partial\\:}{\\partial\\:x}\\left(y\\right)",
"steps": [
{
"type": "step",
"primary": "Derivative of a constant: $$\\frac{d}{dx}\\left({a}\\right)=0$$",
"result": "=0"
}
],
"meta": {
"solvingClass": "Derivatives",
"interimType": "Derivatives",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s79Kg+idP5vLVrjUll6eMdYp9ApVx6pk97jrrFSzJxOAloe9eTz2HvO8muyM4Z1kKdlyEB4JYjIUjkjbDZ4tfSJ3+y6gfQnMr2Alg7BrHl9PbNWyGcX6HZt1LGXH2QGa+Ln0ClXHqmT3uOusVLMnE4CbAGGQy6xiZ+c/G1JYEHGagkt3WiGR7ZaCaXvz77bMjS"
}
},
{
"type": "interim",
"title": "$$\\frac{\\partial\\:}{\\partial\\:x}\\left(z\\right)=0$$",
"input": "\\frac{\\partial\\:}{\\partial\\:x}\\left(z\\right)",
"steps": [
{
"type": "step",
"primary": "Derivative of a constant: $$\\frac{d}{dx}\\left({a}\\right)=0$$",
"result": "=0"
}
],
"meta": {
"solvingClass": "Derivatives",
"interimType": "Derivatives",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s79Kg+idP5vLVrjUll6eMdYp9ApVx6pk97jrrFSzJxOAn3qnIUzgb1GTknQp7LHtUHlyEB4JYjIUjkjbDZ4tfSJ3+y6gfQnMr2Alg7BrHl9PbNWyGcX6HZt1LGXH2QGa+Ln0ClXHqmT3uOusVLMnE4CVJjfiszn29cZ4RF/xvdEEkkt3WiGR7ZaCaXvz77bMjS"
}
},
{
"type": "step",
"result": "=1+0+0"
},
{
"type": "step",
"primary": "Simplify",
"result": "=1",
"meta": {
"solvingClass": "Solver"
}
}
],
"meta": {
"solvingClass": "Derivatives",
"interimType": "Derivatives"
}
},
{
"type": "step",
"result": "=-8\\cdot\\:2\\left(x+y+z\\right)\\cdot\\:1"
},
{
"type": "step",
"primary": "Simplify",
"result": "=-16\\left(x+y+z\\right)",
"meta": {
"solvingClass": "Solver"
}
}
],
"meta": {
"solvingClass": "Derivatives",
"practiceLink": "/practice/derivatives-practice#area=main&subtopic=Partial%20Derivatives",
"practiceTopic": "Partial Derivatives"
}
},
"meta": {
"showVerify": true
}
}
Solution
Solution
Solution steps
Treat as constants
Take the constant out:
Apply the chain rule:
Simplify
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Frequently Asked Questions (FAQ)
What is (\partial)/(\partial x)(-8(x+y+z)^2) ?
The answer to (\partial)/(\partial x)(-8(x+y+z)^2) is -16(x+y+z)