What is the solution for y^{''}+3y=0 ?

The solution for y^{''}+3y=0 is y=c_{1}cos(sqrt(3)t)+c_{2}sin(sqrt(3)t)

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y^{''}+3y=0

y^{^{''}} + 3 y = 0

y = c_{1} cos (3 t) + c_{2} sin (3 t)

Solution steps

y^{''} (t) + 3 y = 0

Solve linear ODE:

y = c_{1} cos (3 t) + c_{2} sin (3 t)

y = c_{1} cos (3 t) + c_{2} sin (3 t)

\int \frac{x ^{2} + 2 x + 3}{x ^{3} - x} d x

\int_{2}^{3} \frac{1}{x - 1} d x

x \to - 4 lim (6 x + 11)

\frac{d}{d x} (x^{2} \cdot tan (\frac{1}{x}))

x \to 0 lim (\frac{1}{cos ( 2 x )})

What is the solution for y^{''}+3y=0 ?
The solution for y^{''}+3y=0 is y=c_{1}cos(sqrt(3)t)+c_{2}sin(sqrt(3)t)